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Popular pages

  • One to Nine - Chapter Eight

    (H) is 2 to the power of about 10 20000. A rather surprising fact is that because this huge number is 10 to the power of about 0.3 &times 10 20000, we may as well say this is ≈ 10 20000. It is much gr...

  • One to Nine - Chapter Five

    2 + ab − b all the pairs are proportional. Let f be the number such that fa = b modulo p. Then this condition is equivalent to f 2 = f + 1 modulo p, i.e. f must be a golden number modulo p. Does t...

  • One to Nine - Ultimate Sudoku

    ONE TO NINE by Andrew Hodges Solution to the ultimate Sudoku This last puzzle does not appear in the original British Short Books 2007 edition, but is included in the 2008 American and Canadian editio...

  • Zigzag permutations and quantum operators

    Zigzag permutations and quantum operators by Andrew Hodges This is a brief introduction to the papers: Andrew Hodges and C. V. Sukumar, Bernoulli, Euler, permutations and quantum algebras, Proc....

  • One to Nine - Chapter Nine

    1/41 = .0243902439... These fit the rule because 2 divides into 10, 3 divides into 36, 4 divides into 100, and 5 divides into 40. Page 302: It is easy to see the every remainder has a unique...

  • One to Nine - Chapter One

    ONE TO NINE by Andrew Hodges Notes, links, updates and answers for Chapter One. Page 3: G H Hardy's 1940 A Mathematician's Apology has remained in print, with an introduction by C. P. Snow. Pa...

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